12x^2+30x-252=0

Solution for 12x^2+30x-252=0 equation:

12x^2+30x-252=0

a = 12; b = 30; c = -252;
Δ = b2-4ac
Δ = 302-4·12·(-252)
Δ = 12996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12996}=114$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-114}{2*12}=\frac{-144}{24}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+114}{2*12}=\frac{84}{24}
=3+1/2
$